Remember: this lab is due on Wednesday
October 3, 2012.
Also wear mismatched clothes for
tomorrow!
No homework for today except to study
for the test on Friday!
Today, we needed to determine how many moles of water are
present in the compound per mole of Copper (II) Sulfate.
Procedure:
First, a clean crucible or flask
must be readied. Then, add a reasonable amount of blue hydrated copper (II)
sulfate to the crucible or flask. Due to the shortage of crucibles, many
students received a flask. Instead, the flask is heated over a Bunsen burner,
evenly applying minimal heat. The substance must be heated until the substance
turns white. Brown indicated overheated. Upon completion, allow the flask to
cool and wipe out any with a tissue or paper towel.
Data
& Conclusion:
Mass of empty crucible
|
19.44
|
17
|
Mass of crucible with
Hydrated Salt
|
21.43
|
19.12
|
Mass of crucible with
Anhydrous salt
|
20.62
|
18.44
|
Calculate the mass of the hydrated salt:
Mass
of crucible with hydrated-Mass of empty flask = Hydrated salt
Calculate
the mass and moles of the water lost.
Mass
of Hydrated Salt – Mass of Anhydrous salt = Water Loss
` Mass of the water / Grams of H2O
Calculate
the mass and moles of anhydrous salt.
Mass
of crucible with anhydrous salt – Mass of empty flask
Mass of anhydrous salt / mass of CuSO4 in grams
Calculate
the ratio between moles of water and moles of anhydrous salt.
Moles
of H2O : Moles of CuSO4
Claim:
What is the formula of the hydrated
salt?
Evidence:
What data did you use to prove your
claim?
Reasoning:
If all of the water was not driven
off, how would this affect your formula for the hydrated salt? Be specific.
Next Scribe: FaBIAN
Signed -Josh-
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