Hey everybody! Not a lot went on today in class, but we did learn a new topic, Solubility rules! People who were present on Wednesday received class time to work on the Reaction Solubility 1 worksheet or the Solubility Rules Lab. People who were absent on Wednesday completed the Solubility Rules Lab.
Homework:
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Due tomorrow: Reaction Solubility 1
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Due tomorrow: Solubility Rules Lab
The worksheet we received today has the common rules for the solubility of compounds. These charts help identify if two compounds will form a precipitate or not.
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Here is a chart that helps identify different ions that are usually soluble in water, which means that they don't form a precipitate. I use the word usually because there are exceptions to the rule. The right side of the chart lists the exceptions that make the compound insoluble.
Example problem:
KNO3 (aq) + NaCl (aq) → KCl (?) + NaNO3 (?)
1. Using our solubility rules we know that all compounds with the K+ ion are soluble which means it dissolves in water and is therefore aqueous (aq).
2. Then, we can determine that all nitrates (NO3-), are also soluble and aqueous (aq).
Final Answer: KNO3 (aq) + NaCl (aq) → KCl (aq) + NaNO3 (aq)
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This chart identifies ions that are usually insoluble in water, which means they do form a precipitate which is a sold. Again, I use the word usually because there are significant exceptions listed on the right side of the chart.
Example problem:
AgNO3 (aq)+
NaOH (aq) → AgOH (?) + NaNO3 (?)
1. Using the chart above, you can conclude that the (OH-) ion is insoluble, and in the reaction, it will not be combined with any ion that makes it soluble. Therefore, we can conclude that (AgOH) will form a precipitate called a solid (s).
2. Using the first chart, you can determine that all (NO3-)compounds are soluble in water and aqueous (aq).
Final Answer: AgNO3 (aq)+ NaOH (aq) → AgOH (s) + NaNO3 (aq)
Now you should have a clear understanding of the solubility rules and how to apply them!
THE NEXT SCRIBE WILL BE:.......Fabian J.
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